Subnetting 2 Different Networks (S2DN)


S2DN:   SOLD       



A. Case Study:

If known;

  • The number of hosts is the date of birth multiplied by the month of birth,
  • If point 1 is worth more than 125, with the number of digits 3, then replace the first value with the number 1,
  • If point 1 is worth more than 125, with more than 3 digits, then select the first 2 NIM digits,
  • The IP Address is class C with the address 194.xx.xx.xx,
  • The first xx is the date of birth and the second xx is the month of birth,

From the knowledge above then please;

  1. Calculate the subnet mask, number of networks, perfix number and write down the last 4 subnets (if the subnet is < 4 then write all of them),
  2. Take the last 2 subnets and make them into different networks and then connect them to the router.

B. Theoretical Basis

GETTING TO KNOW SUBNETTING AND ITS CALCULATION TECHNIQUES

C. Solution:

Given the number of hosts = date x month of birth, then there are 17 x 4 = 68 hosts on each network.

1. Find Host Number

2h ≥ 68
h = 7

Banyaknya host = 2n -- 2
                           = 27 -- 2
                           = 128 -- 2
                           = 126 host / jaringan yang disediakan

2. Find Network Numbers

Angka host = nilai basis -- angka network

7 = 8 -- n
n = 8 -- 7
n = 1\
Banyaknya jaringan = 2n
                                 = 21
                                 = jadi banyaknya jaringan adalah 2

3. Find the Perfix Number

Angka perfix  = 24 + angka network
                      = 24 + 1
                      = 25

192.168.2.0 /25

Subnet mask : 255.255.255.128
11111111 . 11111111 . 11111111 . 10000000
Range 0  : 192.168.2 .0 - 192.168.2 .127
Subnet 0 : 192.168.2 .1 - 192.168.2 .126
Range 1  : 192.168.2 .128 - 192.168.2 .255
Subnet 1 : 192.168.2 .129 - 192.168.2 .254

D. Calculation Results:

1. Subnet mask = 255.255.255.128
2. Number of networks = 2
3. Perfix number = 25
4. Subnet < 4, so the final subnet is:

  • Subnet 0 : 192.168.2.1 - 192.168.2.126
  • Subnet 1 : 192.168.2.129 - 192.168.2.254

E. Simulation:

https://youtu.be/lUO9yVeN40Y

DOWNLOAD TOPOLOGY SIMULATION.pkt 

Broom

Eko Yunianto, S.Kom || NPP : 201430052

Understanding IP Subnets

The rapid development of the internet has caused the use of IP to increase, and the number of available IPs is increasingly depleted. In addition, network settings are also getting bigger because the network is getting bigger. For that, it is necessary to "reduce" the network, namely by creating a subnet (subneting).

So the basic form of IP changes with the increase in subnetwork or subnet number, becoming;

<nomer jaringan><nomer subnet><nomer host>

Networks can be divided into several smaller networks by dividing the IP address with a divider called a subnet mask or commonly called a netmask. Netmasks have the same format as IP addresses.

Example of using subnetmask: 

  • By using the subnet mask 255.255.255.0, this means that our network has 28-2 (254) hosts.
  • By using the subnet mask 255.255.255.240, this means that in the last column of the subnet 240, when converted to binary, becomes 11110000. Bit 0 indicates the number of our hosts, which is 24-2 (14) hosts.

1. Types of subnetting 

There are 2 types of subneting, namely static subneting and variable length subneting.

1.1. Static subnetting

The subnetting used only pays attention to the class of the IP address. For example, for a class C network that only has 4 hosts, subnetting 255.255.255.0 is used. In terms of use, this will make it easier because if there is an additional host, there is no need to change the subnet mask, but it will waste 250 IP addresses.

1.2. Variable Length Subneting Mask (VLSM) 

Subnetting is used based on the number of hosts. So that more networks can be separated.

1.3. Combination of static subnetting and variable length subnetting

The use of subnetting usually uses static subnetting. But because of a need, a small part of the network uses variable length subnetting. So a router is needed to combine the two networks.

2. How to calculate subnets

2.1. Using static subnetting

A network using class A, uses IP 10.252.102.23.

00001010 11111100 01100110 00010111         Alamat 32 bit
    10      252        102           23     Alamat desimal

This means 10 as the network address and 252.102.23 as the host address.

Then the administrator determines that bits 8 to bit 24 are the subnet address. This means using the subnet mask 255.255.255.0 (11111111 11111111 1111111 00000000 in bit notation). With the rule of bits 0 and 1, the network has 216-2 (65534) subnets with each subnet having a maximum number of hosts of 282 (254).

2.2. Using variable length subnetting 

A network uses class C, with IP address 165.214.32.0. The network wants to divide its network into 5 subnets with details: 

  • Subnet #1 : 50 hosts
  • Subnet #2 : 50 hosts
  • Subnet #3 : 50 hosts
  • Subnet #4 : 30 hosts
  • Subnet #5 : 30 hosts.

This cannot be achieved using static subnetting. For this example, if using subnetting 255.255.255.192 then there will only be 4 subnets with each subnet having 64 hosts, which requires 5 subnets. If using subnet 255.255.255.224, it is possible to have up to 8 subnets but each subnet only has a maximum of 32 hosts, whereas what is desired is several subnets with 50 hosts.

The solution is to divide the subnet into 4 subnets using the subnet mask 255.255.255.192 and the last subnet is divided again using the subnet mask 255.255.255.224. So that it will get 5 subnets, with the first to third subnets can get a maximum of 64 hosts and the fourth and fifth subnets have 32 hosts.


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